document.write( "Question 1140604: What is the derivative of y = r / sqrt root of r^2 + 1 \n" ); document.write( "
Algebra.Com's Answer #761428 by MathLover1(20849)\"\" \"About 
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the derivative of \r
\n" ); document.write( "\n" ); document.write( "\"y+=+r+%2F+sqrt%28r%5E2+%2B+1+%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28d%2Fdr%29+%28+r+%2F+sqrt%28r%5E2+%2B+1+%29%29\"=\r
\n" ); document.write( "\n" ); document.write( "Apply the Quotient Rule :\r
\n" ); document.write( "\n" ); document.write( "\"%28f%2Fg%29%27=+%28f%27%2Ag-g%27%2Af%29%2Fg%5E2+\"\r
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\n" ); document.write( "\n" ); document.write( "= ....since \"%28d%2Fdr%29%28r%29=1\" and \"%28d%2Fdr%29%28sqrt%28r%5E2%2B1%29%29+=r+%2F+sqrt%28r%5E2+%2B+1+%29\" , we have\r
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\n" ); document.write( "\n" ); document.write( "= \r
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\n" ); document.write( "\n" ); document.write( "Simplify : \"+%28sqrt%28r%5E2%2B1%29-%28r%2Fsqrt%28r%5E2%2B1%29%29r%29%2F%28sqrt%28r%5E2%2B1%29%5E2%29\": you will get\r
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\n" ); document.write( "\n" ); document.write( "=\"1%2F%28%28r%5E2%2B1%29sqrt%28r%5E2%2B1%29%29+\"\r
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\n" ); document.write( "\n" ); document.write( "or\r
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\n" ); document.write( "\n" ); document.write( "=\"1%2Fsqrt%28%28r%5E2%2B1%29%5E3%29+\"\r
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\n" ); document.write( "\n" ); document.write( "or\r
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\n" ); document.write( "\n" ); document.write( "=\"1%2F%28r%5E2%2B1%29%5E%283%2F2%29+\"\r
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