document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1140882>Question 1140882</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I tried this several times. But unable to factor. <BR>\n" );
document.write( "question is --<BR>\n" );
document.write( "Solve \r<BR>\n" );
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document.write( "2cos^3theta+2costheta-costheta-1=0\r<BR>\n" );
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document.write( "for theta lying between 0 and 360 degrees </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #761402 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=761402\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If this is 2 cos^3 theta+2 cos^2 theta-cos theta-1=0<BR>\n" );
document.write( "(which makes sense, because otherwise you could combine the second and third terms)<BR>\n" );
document.write( "then it factors into (2cos^2 theta-1) (cos theta+1)=0<BR>\n" );
document.write( "and theta =+/- sqrt(2)/2 (45, 135 225, 315 deg)<BR>\n" );
document.write( "and -1 (180 degrees) </SPAN>\n" );
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