document.write( "Question 1140867: A farmer has a field of 70 acres in which he plants potatoes and corn. The seed for potatoes costs $20/acre, the seed for corn costs $60/acre, and the farmer has set aside $3000 to spend on seed. The profit per acre of potatoes is $150 and the profit for corn is $50 an acre. How many acres of each should the farmer plant? \n" ); document.write( "
Algebra.Com's Answer #761391 by Theo(13342)![]() ![]() You can put this solution on YOUR website! total acres are 70. \n" ); document.write( "farmer has seeds to plan either potatoes or corn or both. \n" ); document.write( "seed for potatoes is 20 dollars per acre. \n" ); document.write( "see for corn is 60 dollars per acre. \n" ); document.write( "total money for seed is 3000. \n" ); document.write( "profit per acre of potatoes is 150 dollars. \n" ); document.write( "profit per acre of corn is 50 dollars.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this problem can be solved graphically.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = number of acres of potatoes \n" ); document.write( "y = number of acres of corn.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "objective function is profit = 150 * x + 50 * y\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this is the function you want to maximize.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "constraints are:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x >= 0 \n" ); document.write( "y >= 0 \n" ); document.write( "20 * x + 60 * y <= 3000 \n" ); document.write( "x + y <= 70\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "using the desmos.com calculator, you would graph the opposite of these inequalities.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the area on the graph that is not shaded is your region of feasibility.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the corner points of this area will be where the maximum profit lies.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the graph looks like this:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " ![]() \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the corner points of the reasible region are:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(0,50), (30,40), (70,0), (0,0)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "profit at each of these corner points are:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "0 * 150 + 50 * 50 = 2500 for (0,50) \n" ); document.write( "30 * 150 + 40 * 50 = 6500 for (30,40) \n" ); document.write( "70 * 150 + 0 * 50 = 10500 for (70,0) ***** \n" ); document.write( "0 * 150 + 0 * 50 = 0 for (0,0)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "maximum profit is attained when all 70 acres are planted by potatoes.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "all constraints need to be satisfied as well.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "constraints are:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x >= 0 = satisfied \n" ); document.write( "y >= 0 = satisfied \n" ); document.write( "20 * x + 60 * y <= 3000 = 20 * 70 + 60 * 0 <=3000 = 1400 <= 3000 = satisfied \n" ); document.write( "x + y <= 70 = 70 + 0 <= 70 = 70 <= 70 = satisfied.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "all constraints were satisfied, therefore the solution looks good.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the solution is that all 70 acres should be planted by potatoes for maximum profit, based on the information provided in the problem.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |