document.write( "Question 1140876: A man has $295,000 invested in three properties. One earns 12%, one 10% and one 8%. His annual income from the properties is $28,100 and the amount invested at 8% is twice that invested at 12%.
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Algebra.Com's Answer #761386 by ikleyn(52798) $\"\"$ $\"About$

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document.write( "The question (which you forgot to formulate) is to find each investment.\r\n" );
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document.write( "Let x be the amount invested at 12% (in dollars).\r\n" );
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document.write( "Then the amount invested at 8% is (2x) dollars, according to the condition;\r\n" );
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document.write( "the amount invested at 10% is the rest  (295000-x - 2x) = (295000-3x)  dollars.\r\n" );
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document.write( "The money equation is the total income from three properties\r\n" );
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document.write( "    0.08*(2x) + 0.1*(295000-3x) + 0.12*x = 28100.\r\n" );
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document.write( "It is the equation for one single unknown, which you can easily solve.\r\n" );
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document.write( "When you solve it and will find x, do not forget to calculate all other participating amounts.\r\n" );
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