document.write( "Question 1140692: Determine the eccentricity, the type of conic, and the directrix.\r
\n" ); document.write( "\n" ); document.write( "r = (9)/(5 +6 cos θ)
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Algebra.Com's Answer #761377 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "given:\r
\n" ); document.write( "\n" ); document.write( "\"r+=+9%2F%285+%2B6cos%28theta%29%29+\"\r
\n" ); document.write( "\n" ); document.write( "find:
\n" ); document.write( "the type of conic
\n" ); document.write( "the eccentricity
\n" ); document.write( " the directrix:\r
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\n" ); document.write( "\n" ); document.write( "Standard form for conics in polar equations is \r
\n" ); document.write( "\n" ); document.write( "\"r+=%28ep%29%2F%281+%2B-+e%2Acos%28theta%29%29\"\r
\n" ); document.write( "\n" ); document.write( "where \"e\" is the eccentricity, the directrix is \"x\" = ±\"p\" if \"cosine\"\r
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\n" ); document.write( "\n" ); document.write( "in your case: \r
\n" ); document.write( "\n" ); document.write( "\"r+=+9%2F%285+%2B6cos%28theta%29%29\" multiply the numerator and denominator by \"1%2F5\"\r
\n" ); document.write( "\n" ); document.write( "\"r+=+9%281%2F5%29%2F%285%281%2F5%29+%2B%281%2F5%296cos%28theta%29%29\" \r
\n" ); document.write( "\n" ); document.write( "\"r+=+%289%2F5%29%2F%281+%2B%286%2F5%29cos%28theta%29%29+\"\r
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\n" ); document.write( "\n" ); document.write( "the eccentricity:\r
\n" ); document.write( "\n" ); document.write( "\"e=6%2F5\"\r
\n" ); document.write( "\n" ); document.write( "the directrix:\r
\n" ); document.write( "\n" ); document.write( "since \"ep=9%2F5\"=>\"p=%289%2F5%29%2Fe\"...substitute \"e\"\r
\n" ); document.write( "\n" ); document.write( "=>\"p=%289%2F5%29%2F%286%2F5%29\"
\n" ); document.write( "=>\"p=%289%2F6%29\"
\n" ); document.write( "=>\"p=%283%2F2%29\"\r
\n" ); document.write( "\n" ); document.write( "so, the directrix is \"x+=+p+\"=> \"x=3%2F2\"
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\n" ); document.write( "the type of conic:\r
\n" ); document.write( "\n" ); document.write( "since \"e%3E1\", you have \"+hyperbola\"\r
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