document.write( "Question 1140855: Suppose that the function g is defined on the interval (-2,2] as follows \r
\n" ); document.write( "\n" ); document.write( " h(x)=
\n" ); document.write( "-1 if -2 < x <= -1
\n" ); document.write( "0 if -1 < x <= 0
\n" ); document.write( "1 if 0 < x <= 1
\n" ); document.write( "2 if 1 < x <= 2 \r
\n" ); document.write( "\n" ); document.write( "find h(-1) =
\n" ); document.write( " h(-0.5)=
\n" ); document.write( " h (2) =\r
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Algebra.Com's Answer #761364 by ikleyn(52810) $\"\"$ $\"About$

You can put this solution on YOUR website!
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\n" ); document.write( "Suppose that the function $\"highlight%28cross%28g%29%29\"$ h is defined on the interval (-2,2] as follows \r
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document.write( " h(x)=\r\n" );
document.write( "        -1   if -2 < x <= -1        (1)\r\n" );
document.write( "         0   if -1 < x <= 0         (2)\r\n" );
document.write( "         1   if 0 < x <= 1          (3)\r\n" );
document.write( "         2   if 1 < x <= 2          (4)\r\n" );
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document.write( "find h(-1).                 Formula (1) works.   Substitute and calculate.\r\n" );
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document.write( "     h(-0.5).               Formula (2) works.   Substitute and calculate.\r\n" );
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document.write( "     h (2).                 Formula (4) works.   Substitute and calculate.\r\n" );
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\n" ); document.write( "\n" ); document.write( "Find my instructions placed in your post, and follow them.\r
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\n" ); document.write( "\n" ); document.write( "Happy calculations !\r
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