document.write( "Question 1140728: Consider a normal population with a mean of 50 and standard deviation of 2.Find the probability that a randomly picked number is between 49.1 and 50.15. \n" ); document.write( "
Algebra.Com's Answer #761314 by Boreal(15235) You can put this solution on YOUR website! z=(x-mean)/sd \n" ); document.write( "so z is between (49.1-50)/2=-.9/2=-0.45 \n" ); document.write( "and (50.15-50)/2=0.15/2=+0.075 \n" ); document.write( "that probability is 0.2035 \n" ); document.write( " |