document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=104600>Question 104600</A>: <I><SPAN STYLE=\"word-break: break-all;\"> having a difficult time with finding the answer to a - 8 = 23? how do i solve a? and 13 + z = 6 how do I solve for z<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #76121 by </B><A HREF=/tutors/aboutme.mpl?userid=kingster64><B>kingster64(2)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=kingster64><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=76121\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> For the first one you will need to isolate a by adding 8 to both sides. Therefore, a will equal 23+8 = 31 <BR>\n" );
document.write( "a=31\r<BR>\n" );
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document.write( "a-8 = 31<BR>\n" );
document.write( "a+ 8 = 8 ( the negative 8 plus positive will cancel each other out and leave a)<BR>\n" );
document.write( "a=31    </SPAN>\n" );
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