document.write( "Question 1140669: 1. through: (5,4), parallel to y=0\r
\n" ); document.write( "\n" ); document.write( "2. through:(3,-3), parallel to y=1/4x+5
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\n" ); document.write( "3. through:(1,4), perp. to y=-1/3x\r
\n" ); document.write( "\n" ); document.write( "4. through:(2,-1), perp. to y=-x-1\r
\n" ); document.write( "\n" ); document.write( "5. through:(-3,0), perp. to y=-3/5-1\r
\n" ); document.write( "\n" ); document.write( "6. through:(-4,1), perp. to y=0
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Algebra.Com's Answer #761191 by josgarithmetic(39618)\"\" \"About 
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\n" ); document.write( "1. through: (5,4), parallel to y=0
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\n" ); document.write( "\n" ); document.write( "This means y=4;
\n" ); document.write( "all x values are included.\r
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\n" ); document.write( "\n" ); document.write( "For the other questions y=mx+b has slope m.
\n" ); document.write( "You could use the point-slope equation form for any included point (h,k); and for parallel, slope m; for perpendicular to given line, slope \"-1%2Fm\".\r
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\n" ); document.write( "\n" ); document.write( "#6 is different. Perpendicular to y=0 will mean, slope is undefined and you want a line that is vertical.
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