document.write( "Question 1140655: $5,581 is invested, part at 15% and the rest at 6%. If the interest earned from the amount invested at 15% exceeds the interest earned from the amount invested at 6% by $261.54, how much is invested at each rate? (Round to two decimal places if necessary.)
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Algebra.Com's Answer #761175 by greenestamps(13200) $\"\"$ $\"About$

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\n" ); document.write( "Let x be the amount invested at 15%; then the amount invested at 6% is 5581-x.

\n" ); document.write( "The interest from x at 15% is .15(x); the interest from (5581-x) at 6% is.06(5581-x).

\n" ); document.write( "The problem says the amount of interest earned at 15% is 261.54 more than the interest earned at 6%:

\n" ); document.write( " $\".15%28x%29+=+.06%285581-x%29+%2B+261.54\"$

\n" ); document.write( "Solve using basic algebra. \n" ); document.write( "

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