document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1140588>Question 1140588</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Explain, with words and examples, when graphing equations of lines is easier using the y-intercept/slope method versus the x and y intercept method and when graphing equations of lines is easier using the x and y intercept method versus y-intercept/slope method.  </SPAN>\n" );
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document.write( "Two points determine a line.  So the question is about how much effort it takes to find two points for a given equation.<br><BR>\n" );
document.write( "If the equation is given in Ax+By=C form, then it is easiest to set x=0 to find the y-intercept and set y=0 to find the x-intercept.  For example....<br><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3x%2B4y=12 ALIGN=MIDDLE  ALT=\"3x%2B4y=12\"   DISABLED_style= \"max-width:90%; height:auto;\" ><br><BR>\n" );
document.write( "When x=0, y = 12/4 = 3, so one point is (0,3); when y=0, x = 12/3 = 4, so the second point is (4,0).<br><BR>\n" );
document.write( "If the equation is given in y=Ax+B form, you immediately know the slope and the y-intercept.  So the first point is the y-intercept, and a second point can be found using the y-intercept and the slope.  For example....<br><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=+-2x%2B5 ALIGN=MIDDLE  ALT=\"y+=+-2x%2B5\"   DISABLED_style= \"max-width:90%; height:auto;\" ><br><BR>\n" );
document.write( "The y-intercept (when x=0) is 5, so the first point is (0,5).<br><BR>\n" );
document.write( "A second point can be found starting at the known first point and moving according to the slope of -2.  A slope of -2 means 1 unit right and 2 units down from the known point (0,5), giving you a second point (1,3).<br><BR>\n" );
document.write( "You can provide your own additional examples, and further explanation, if required. </SPAN>\n" );
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