document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1140561>Question 1140561</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How long does it take for $1875 to double if it is invested at 10% compounded continuously? Round your answer to two decimal places, if necessary. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #761098 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=761098\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P=Poe^rt, to double, P=2Po, or P/Po=2<BR>\n" );
document.write( "2=e^rt<BR>\n" );
document.write( "ln 2=rt<BR>\n" );
document.write( "0.693=.10*t<BR>\n" );
document.write( "t=6.93 years.  The rule of 70 would say 7 years.  Note that the amount of money is irrelevant if all one wants is the doubling time. </SPAN>\n" );
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