document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1140553>Question 1140553</A>: <I><SPAN STYLE=\"word-break: break-all;\">  A new type of pump can drain a certain pool in 6 hours.  An older pump can drain the pool in 14 hours.  How long will it take both pumps working together to drain the pool ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #761083 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=761083\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let t be the hours it takes both pumps working together to drain the pool<BR>\n" );
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document.write( "1/6 + (1/14) = (14 + 6)/84 = 20/84 = 10/42<BR>\n" );
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document.write( "working together, the pumps do 10/42 of the job in 1 hour<BR>\n" );
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document.write( "also working together they do 1/t per hour, then<BR>\n" );
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document.write( "10/42 = 1/t<BR>\n" );
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document.write( "invert the two fractions and solve for t<BR>\n" );
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document.write( "t = 42/10<BR>\n" );
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document.write( "t = 4.2<BR>\n" );
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document.write( "working together, they empty the pool in 4.2 hours<BR>\n" );
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document.write( "  </SPAN>\n" );
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