document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1140546>Question 1140546</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A technician is launching fireworks near the end of a show.  Of the remaining twelve fireworks, six are blue and six are red.  If she launches 5 of them in a random order, what is the probability that at least two of them are blue ones? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #761070 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=761070\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 12C5 are the number of choices of 5 from 12<BR>\n" );
document.write( "look at 1 or 0 are blue, and take the complement of that.<BR>\n" );
document.write( "for 1: 6C1*6C4=6*15=90 possibilities<BR>\n" );
document.write( "for 0: 6C5 or 6 ways<BR>\n" );
document.write( "96 possibilities from 792=0.1212 probability they won't be or 0.8787 probability at least two are blue.\r<BR>\n" );
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document.write( "check<BR>\n" );
document.write( "2 blue are 6C2*6C3=15*20=300<BR>\n" );
document.write( "3 blue are 6C3*6C2=also 300 <BR>\n" );
document.write( "4 blue are 6C4*6C1=90<BR>\n" );
document.write( "5 blue are 6 ways<BR>\n" );
document.write( "And those are the other 696 possibilities.<BR>\n" );
document.write( "696/792=0.8787 ANSWER </SPAN>\n" );
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