document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1140494>Question 1140494</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A research group conducted an extensive survey of 3169 wage and salaried workers on issues ranging from relationships with their bosses to household chores. The data were gathered through hour-long telephone interviews with a nationally representative sample. In response to the question, \"What does success mean to you?\" 1508 responded, \"Personal satisfaction from doing a good job.\" Let p be the population proportion of all wage and salaried workers who would respond the same way to the stated question. Find a 90% confidence interval for p. (Round your answers to three decimal places.) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #761068 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=761068\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A 90% CI is phat +/-z* sqrt(p*(1-p)/n),  z=1.645<BR>\n" );
document.write( "phat =0.4759<BR>\n" );
document.write( "so the half-interval is z* sqrt(.4759*.5241/3169)=0.00887*1.645=0.0146<BR>\n" );
document.write( "the interval is (0.461, 0.491) </SPAN>\n" );
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