document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1140539>Question 1140539</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A jeep went up a mountain trail at a speed of 25 mph, and came back down the mountain trail at a speed of 75 mph.  What was the average speed for the round trip </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #761062 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=761062\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Assume it went up 25 miles, so it took an hour<BR>\n" );
document.write( "It came down in 1/3 of an hour, so 50 miles took 4/3 hours or 37.5 mph\r<BR>\n" );
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document.write( "It comes down 3 times faster than it goes up, so the increased speed coming down is applied only 1/3 as much<BR>\n" );
document.write( "3/4 of the time (1 hour/1 1/3 hours) it is going 25 mph and 1/4 of the time 75 mph<BR>\n" );
document.write( "(3/4)*25+(1/4)75=37.5 mph<BR>\n" );
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