document.write( "Question 104577This question is from textbook algebra Structure and Method
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document.write( ": Here is another problem!
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document.write( "Jo has 37 coins(all nickles, dimes and quarters) worth $5.50. She has 4 more quarters than nickles. How many dimes does Jo have? I can't figure out what the variable for dimes is.\r
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document.write( "Thanks! \n" );
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Algebra.Com's Answer #76106 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Jo has 37 coins(all nickles, dimes and quarters) worth $5.50. She has 4 more quarters than nickles. How many dimes does Jo have? I can't figure out what the variable for dimes is. \n" ); document.write( "------------------------- \n" ); document.write( "Let number of nickels be \"x\" ; value of these is 5x cents \n" ); document.write( "# of quarters is \"x+4\" ; value of these is 25(x+4) = 25x+100 cents \n" ); document.write( "# of dimes = 37-(x+x+4)=\"33-2x\"; value is 10(33-2x)=330-20x cents \n" ); document.write( "------------------------- \n" ); document.write( "EQUATION: \n" ); document.write( "value + value + value = 550 cents \n" ); document.write( "5x + 25x+100 + 330-20x = 550 \n" ); document.write( "10x = 120 \n" ); document.write( "x = 12 (# of nickels) \n" ); document.write( "x+4 = 16 (# of quarters) \n" ); document.write( "33-2x= 9 (# of dimes) \n" ); document.write( "======================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |