document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1140518>Question 1140518</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve by any method\r<BR>\n" );
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document.write( "{5x-2y=31<BR>\n" );
document.write( "{2x-y=-13 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #761039 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=761039\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "In my opinion, when the two equations are both in Ax+By=C form, elimination is easiest.<br><BR>\n" );
document.write( "(1) multiply the second equation by -2 and add to the first equation<BR>\n" );
document.write( "(2) that eliminates y, giving you a single equation in x that you can solve<BR>\n" );
document.write( "(3) then substitute that value of x in either of the original equations to get an equation in y that you can solve to finish the problem </SPAN>\n" );
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