document.write( "Question 15119: the supplement of an angle measures 25 degrees more than twice its complement. Find the measure of the angle.\r
\n" ); document.write( "\n" ); document.write( "My work: 180-x= 2(90-x)\r
\n" ); document.write( "\n" ); document.write( " 180-x= 180-2x\r
\n" ); document.write( "\n" ); document.write( " 180+x=180\r
\n" ); document.write( "\n" ); document.write( " x=1 BUT, x is suppposed to be equal to 25 inthe answer key.
\n" ); document.write( "Thank you.
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Algebra.Com's Answer #7610 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
I would let x = the complement, since that is at the end of the first sentence.
\n" ); document.write( "2x + 25 = the supplement\r
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\n" ); document.write( "\n" ); document.write( "The equation is based upon the fact that if you subtract the supplement minus the complement, you get 90 degrees.
\n" ); document.write( "2x + 25 - x = 90
\n" ); document.write( "x + 25 = 90
\n" ); document.write( "x= 65 complement
\n" ); document.write( "90-x = 25 = the angle \r
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\n" ); document.write( "\n" ); document.write( "There may be easier ways to do this if we think about it, but at least this works to solve the problem. \r
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\n" ); document.write( "\n" ); document.write( "OH! I see it!! THE WAY YOU DID IT IS CORRECT!! YOU JUST FORGOT THE 25.\r
\n" ); document.write( "\n" ); document.write( "Your equation: 180-x= 2(90-x)
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\n" ); document.write( "Should have been: 180-x= 2(90-x)+ 25\r
\n" ); document.write( "\n" ); document.write( "This works!! x= 25. \r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC
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