document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1140209>Question 1140209</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A bottle of soda at room temperature (72 F) is placed in a refrigerator where the temperature is 44 F. After half an hour, the soda has cooled to 61 F. What is the temperature of the soda after another half hour?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #760970 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13209)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=760970\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "I don't know why anyone would say that the temperature of the soda will continue to cool by 11 degrees per hour, when the temperature of the refrigerator is 44 degrees....<br><BR>\n" );
document.write( "Newton's law of cooling says that the rate of cooling is proportional to the difference between the two temperatures.<br><BR>\n" );
document.write( "Initially, the difference between the temperatures of the soda and refrigerator was 28 degrees.<br><BR>\n" );
document.write( "In the first half hour, the temperature of the soda decreased from 72 to 61 degrees, a decrease of 11 degrees.<br><BR>\n" );
document.write( "This means that from the beginning to the end of each half hour, the temperature will decrease by 11/28 of the difference between the two temperatures at the beginning of the half hour.<br><BR>\n" );
document.write( "Take the difference between the temperatures of the soda and the refrigerator at the beginning of the second half hour and multiply it by 11/28.  That will give you the amount of cooling in the second half hour; subtract that from the temperature at the beginning of the second half hour to find the temperature of the soda at the end of the second half hour.<br><BR>\n" );
document.write( "You will get the answer shown by the other tutor. </SPAN>\n" );
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