document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1140376>Question 1140376</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Would somebody help me reduce expression to lowest terms? it's this one here:\r<BR>\n" );
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document.write( "x^2-4/8-x^3\r<BR>\n" );
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document.write( "Thanks in advance! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #760886 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=760886\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> this is (x+2)(x-2) for numerator, difference of squares<BR>\n" );
document.write( "divided by (2-x)(4+2x+x^2) difference of cubes<BR>\n" );
document.write( "The x-2 cancels IF we multiply the denominator by -1 and the whole fraction by -1.<BR>\n" );
document.write( "Then we have -(x+2)/(4+2x+x^2)\r<BR>\n" );
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document.write( "The second - turns (2-x) into (x-2), which can cancel. <BR>\n" );
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