document.write( "Question 1140367: Find the periodic payment for each sinking fund that is needed to accumulate the given sum under the given conditions. (Round your answer to the nearest cent.)
\n" ); document.write( "FV = $2,200,000, r = 2%, compounded weekly for 15 years\r
\n" ); document.write( "\n" ); document.write( "ANY AND ALL HELP IS APPRECIATED! :)
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Algebra.Com's Answer #760879 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
using my Texas Instruments Business Analyst II calculator, i do the following:\r
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\n" ); document.write( "\n" ); document.write( "present value = 0
\n" ); document.write( "future value = 2200000
\n" ); document.write( "periodic payment = 0
\n" ); document.write( "interest rate per time period = 2% per year / 52 = .038461538% per week
\n" ); document.write( "number of time periods = 15 years * 52 = 780 weeks
\n" ); document.write( "payments are made at the end of each time period\r
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\n" ); document.write( "\n" ); document.write( "i click on payment (PMT) and the calculator tells me that the payment at the end of each time period (end of each week) is equal to -2,419.096403.\r
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\n" ); document.write( "\n" ); document.write( "the payment is shown as negative because it's money going out, while the 2,200,000 future value is shown as positive because it's money coming in.\r
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\n" ); document.write( "\n" ); document.write( "you can do the same with the following online calculator.\r
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\n" ); document.write( "\n" ); document.write( "https://arachnoid.com/finance/\r
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\n" ); document.write( "\n" ); document.write( "here's a display of the result.\r
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\n" ); document.write( "\n" ); document.write( "you can also do this by formula.\r
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\n" ); document.write( "\n" ); document.write( "the formula is in the following reference.\r
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\n" ); document.write( "\n" ); document.write( "https://www.algebra.com/algebra/homework/Finance/THEO-2016-04-29.lesson#f3\r
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\n" ); document.write( "\n" ); document.write( "the particular formula to solve this kind of problem is shown below.\r
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\n" ); document.write( "\n" ); document.write( "ANNUITY FOR A FUTURE AMOUNT WITH END OF TIME PERIOD PAYMENTS \r
\n" ); document.write( "\n" ); document.write( "a = (f*r)/((1+r)^n-1) \r
\n" ); document.write( "\n" ); document.write( "a is the annuity.
\n" ); document.write( "f is the future amount.
\n" ); document.write( "r is the interest rate per time period.
\n" ); document.write( "n is the number of time periods. \r
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\n" ); document.write( "\n" ); document.write( "in this formula, the interest rate is the percent divided by 100 and all inputs are positive.\r
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\n" ); document.write( "\n" ); document.write( "you still need to get the interest rate per time period and the number of time periods.\r
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\n" ); document.write( "\n" ); document.write( "since the time periods are in weeks, you would do the following.\r
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\n" ); document.write( "\n" ); document.write( "interest rate per time period = 2% / 100 = .02 per year / 52 = .0003846153846 per week.\r
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\n" ); document.write( "\n" ); document.write( "number of time periods = 15 years * 52 weeks per year = 780 weeks.\r
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\n" ); document.write( "\n" ); document.write( "your inputs to this formula are shown below.\r
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\n" ); document.write( "\n" ); document.write( "a = (f*r)/((1+r)^n-1) becomes:\r
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\n" ); document.write( "\n" ); document.write( "a = (2200000*.0003846153846)/((1+.0003846153846)^780-1)\r
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\n" ); document.write( "\n" ); document.write( "the result is a = 2419.096404\r
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