document.write( "Question 1140305: if line PQ passes through (1,2) and perpendicular to y=5x-1, determined the equation of PQ.\r
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document.write( "If the gradient of AB,is 15, 3,and line PQ is parrell to line AB,and passes through point (-4,5) for the equation of line AB \n" );
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Algebra.Com's Answer #760816 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! The slope of a line perpendicular to line with slope 5 is -1/5 (negative reciprocal) \n" ); document.write( "point slope formula y-y1=m(x-x1) \n" ); document.write( "y-2=(-1/5)(x-1) \n" ); document.write( "y=(-1/5)x+11/5 (1/5+2)\r \n" ); document.write( "\n" ); document.write( "The slope of AB is 5; parallel lines have the same slope \n" ); document.write( "y-5=5(x+4), note signs \n" ); document.write( "y=5x+25\r \n" ); document.write( "\n" ); document.write( " |