document.write( "Question 1140305: if line PQ passes through (1,2) and perpendicular to y=5x-1, determined the equation of PQ.\r
\n" ); document.write( "\n" ); document.write( "If the gradient of AB,is 15, 3,and line PQ is parrell to line AB,and passes through point (-4,5) for the equation of line AB
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Algebra.Com's Answer #760816 by Boreal(15235)\"\" \"About 
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The slope of a line perpendicular to line with slope 5 is -1/5 (negative reciprocal)
\n" ); document.write( "point slope formula y-y1=m(x-x1)
\n" ); document.write( "y-2=(-1/5)(x-1)
\n" ); document.write( "y=(-1/5)x+11/5 (1/5+2)\r
\n" ); document.write( "\n" ); document.write( "The slope of AB is 5; parallel lines have the same slope
\n" ); document.write( "y-5=5(x+4), note signs
\n" ); document.write( "y=5x+25\r
\n" ); document.write( "\n" ); document.write( "\"graph%28300%2C300%2C-10%2C10%2C-10%2C10%2C5x-1%2C%28-1%2F5%29x%2B11%2F5%29%29\"
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