document.write( "Question 1140275: A box contains $7.55 in nickels, dimes, and quarters. There are 44 coins in all, and the sum of the numbers of nickels and dimes is 2 less than the number of quarters. How many coins of each kind are there? \n" ); document.write( "
Algebra.Com's Answer #760765 by Boreal(15235)\"\" \"About 
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nickels=x
\n" ); document.write( "dimes=y
\n" ); document.write( "quarters=z
\n" ); document.write( "x+y+z=44
\n" ); document.write( "x+y=z-2
\n" ); document.write( "so z-2+z=44
\n" ); document.write( "2z=46
\n" ); document.write( "z=23 quarters (5.75)ANSWER
\n" ); document.write( "x nickels
\n" ); document.write( "23-x dimes
\n" ); document.write( ".05x+.10(23-x)=1.80 (the difference between 5.75 and 7.55)
\n" ); document.write( ".05X+2.30-.10X=1.80
\n" ); document.write( "-.05X=-0.50
\n" ); document.write( "x=10 nickels (0.50) ANSWER
\n" ); document.write( "23-x=13 dimes (1.30)ANSWER
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