document.write( "Question 1140275: A box contains $7.55 in nickels, dimes, and quarters. There are 44 coins in all, and the sum of the numbers of nickels and dimes is 2 less than the number of quarters. How many coins of each kind are there? \n" ); document.write( "
Algebra.Com's Answer #760765 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! nickels=x \n" ); document.write( "dimes=y \n" ); document.write( "quarters=z \n" ); document.write( "x+y+z=44 \n" ); document.write( "x+y=z-2 \n" ); document.write( "so z-2+z=44 \n" ); document.write( "2z=46 \n" ); document.write( "z=23 quarters (5.75)ANSWER \n" ); document.write( "x nickels \n" ); document.write( "23-x dimes \n" ); document.write( ".05x+.10(23-x)=1.80 (the difference between 5.75 and 7.55) \n" ); document.write( ".05X+2.30-.10X=1.80 \n" ); document.write( "-.05X=-0.50 \n" ); document.write( "x=10 nickels (0.50) ANSWER \n" ); document.write( "23-x=13 dimes (1.30)ANSWER \n" ); document.write( " \n" ); document.write( " |