document.write( "Question 1140236: You travel the first 48 miles of a journey at an average of 36 mph and the second 48 miles at an average of v mph. What must be v if you want to average 45 mph over the 96 mile journey?
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Algebra.Com's Answer #760735 by josgarithmetic(39631)\"\" \"About 
You can put this solution on YOUR website!
total time:
\n" ); document.write( "\"48%2F36%2B48%2Fv\"\r
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\n" ); document.write( "\n" ); document.write( "total distance:
\n" ); document.write( "\"96\" \"miles\"\r
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\n" ); document.write( "\n" ); document.write( "EQUATION
\n" ); document.write( "\"96%2F%2848%2F36%2B48%2Fv%29=45\"-----solve for v.\r
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\n" ); document.write( "\n" ); document.write( "\"2%2F%281%2F36%2B1%2Fv%29=45\"\r
\n" ); document.write( "\n" ); document.write( "\"2%2F%28%28v%2B36%29%2F36v%29=45\"\r
\n" ); document.write( "\n" ); document.write( "\"%282%2A36v%29%2F%28v%2B36%29=45\"\r
\n" ); document.write( "\n" ); document.write( "\"%282%2A12v%29%2F%28v%2B36%29=15\"\r
\n" ); document.write( "\n" ); document.write( "\"%282%2A4v%29%2F%28v%2B36%29=5\"\r
\n" ); document.write( "\n" ); document.write( "\"8v=5%28v%2B36%29\"\r
\n" ); document.write( "\n" ); document.write( "\"8v=5v%2B5%2A36\"\r
\n" ); document.write( "\n" ); document.write( "\"3v=5%2A3%2A12\"\r
\n" ); document.write( "\n" ); document.write( "\"v=60\"
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