document.write( "Question 1140195: A radioactive substance decays according to A=A0e−0.0048t, where A0 is the initial amount and t is the time in years. If A0=580 grams, find the time for the radioactive substance to decay to 405 grams. Round your answer to two decimal places, if necessary. \n" ); document.write( "
Algebra.Com's Answer #760684 by josgarithmetic(39620)\"\" \"About 
You can put this solution on YOUR website!
-----------------------------------------------------------------------------
\n" ); document.write( "A=A0e−0.0048t \"A=A%5Bo%5De%5E%28-0.0048t%29\", where A0 is the initial amount and t is the time in years. If A0=580 grams, find the time for the radioactive substance to decay to 405 grams.
\n" ); document.write( "-------------------------------------------------------------------------------\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"ln%28A%29=ln%28A%5Bo%5D%29%2Bln%28e%5E%28-0.0048t%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\"ln%28A%29=ln%28A%5Bo%5D%29-0.0048t\"\r
\n" ); document.write( "\n" ); document.write( "\"ln%28A%29-ln%28A%5Bo%5D%29=-0.0048t\"\r
\n" ); document.write( "\n" ); document.write( "\"ln%28A%5Bo%5D%29-ln%28A%29=0.0048t\"\r
\n" ); document.write( "\n" ); document.write( "\"t=%28ln%28A%29-ln%28A%5Bo%5D%29%29%2F0.0048\"
\n" ); document.write( "This is as a formula. You substitute the given values and evaluate.
\n" ); document.write( "
\n" );