document.write( "Question 104541: Nlog base 2 N=3500 I tried base changes
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document.write( "log 3500=log N^N/(log 2)
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document.write( "(log 3500) (log 2)=log N^N
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document.write( "(3.54)(.301)=log N^N
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document.write( "1.066=log N^N
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document.write( "10^1.066=N^N
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document.write( "11.62=N^N
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document.write( "N is about 3.4
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document.write( "It doesn't check out Help please \n" );
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Algebra.Com's Answer #76066 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Nlog base 2 N=3500 I tried base changes \n" ); document.write( "log 3500=log N^N/(log 2) \n" ); document.write( "(log 3500) (log 2)=log N^N \n" ); document.write( "(3.54)(.301)=log N^N \n" ); document.write( "1.066=log N^N \n" ); document.write( "10^1.066=N^N \n" ); document.write( "11.62=N^N \n" ); document.write( "N= 11.62^(1/N) \n" ); document.write( "Nlog base 2 N=3500 I tried base changes \n" ); document.write( "log 3500=log N^N/(log 2) \n" ); document.write( "(log 3500) (log 2)=log N^N \n" ); document.write( "(3.54)(.301)=log N^N \n" ); document.write( "1.066=log N^N \n" ); document.write( "10^1.066=N^N \n" ); document.write( "11.62=N^N \n" ); document.write( "N = 11.62^(1/N) \n" ); document.write( "------------ \n" ); document.write( "I graphed y=x and y=11.62^(1/x) on the same screen and \n" ); document.write( "found their intersection at x = 2.5838137 \n" ); document.write( "--------------- \n" ); document.write( "Checking: \n" ); document.write( "11.62 = 2.5838137^2.5838137 \n" ); document.write( "11.62 = 11.61999999999... \n" ); document.write( "========== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |