document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1140123>Question 1140123</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The speedboat traveled at a speed that was twice as fast at the yacht. The speedboat traveled 240 miles in one hour less than it took the yacht to travel 150 miles. What were the speed and time for both the speedboat and the yacht? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #760601 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=760601\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> distance=speed*time<BR>\n" );
document.write( "yacht=x speed<BR>\n" );
document.write( "speedboat=2x speed\r<BR>\n" );
document.write( "\n" );
document.write( "so 150=x*t1<BR>\n" );
document.write( "240=2x*(t1-1)<BR>\n" );
document.write( "300=2x*t1, multiplying the top by 2<BR>\n" );
document.write( "240/(t1-1)=300/t1<BR>\n" );
document.write( "cross-multiply<BR>\n" );
document.write( "240 t1=300t1-300<BR>\n" );
document.write( "-60 t1=-300<BR>\n" );
document.write( "t1=5 hours for yacht and speed is 30 mph<BR>\n" );
document.write( "t2=4 hours for speedboat and speed is 60 mph </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );