document.write( "Question 1140014: Starting salaries of 90 college graduates who have taken a statistics course have a mean of $42,432 and a standard deviation of $10,854.
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document.write( "Using a 0.91 degree of confidence, find both of the following:
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document.write( "A. The margin of error E
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document.write( "B. The confidence interval for the mean μ:
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document.write( " <μ< \n" );
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Algebra.Com's Answer #760544 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! half-interval is t df=89*s/sqrt(n) \n" ); document.write( "t=1.714 \n" ); document.write( "E=1.714*10854/sqrt(90)=$1961.01 or $1961 \n" ); document.write( "91% CI is ($40471, $44393), the mean +/- the error\r \n" ); document.write( "\n" ); document.write( "if one uses a z-test then z=1.695 \n" ); document.write( "and the interval width is 1939.27 or $1939 and the interval is ($40493, $44371) \n" ); document.write( " |