document.write( "Question 1140014: Starting salaries of 90 college graduates who have taken a statistics course have a mean of $42,432 and a standard deviation of $10,854.
\n" ); document.write( "Using a 0.91 degree of confidence, find both of the following:
\n" ); document.write( "A. The margin of error E
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\n" ); document.write( "B. The confidence interval for the mean μ:
\n" ); document.write( " <μ<
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Algebra.Com's Answer #760544 by Boreal(15235)\"\" \"About 
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half-interval is t df=89*s/sqrt(n)
\n" ); document.write( "t=1.714
\n" ); document.write( "E=1.714*10854/sqrt(90)=$1961.01 or $1961
\n" ); document.write( "91% CI is ($40471, $44393), the mean +/- the error\r
\n" ); document.write( "\n" ); document.write( "if one uses a z-test then z=1.695
\n" ); document.write( "and the interval width is 1939.27 or $1939 and the interval is ($40493, $44371)
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