document.write( "Question 104530: Solve the following system.\r
\n" ); document.write( "\n" ); document.write( "3x - 6y = 9
\n" ); document.write( "x -2y = 3\r
\n" ); document.write( "\n" ); document.write( "Is this going to turn into a fraction? If so, how do I do it? Not sure. Thank you for your helpin getting me going in the right direction..
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Algebra.Com's Answer #76054 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
I don't think you can predict whether it'll turn into a fraction until you're working through it. Let's start.
\n" ); document.write( "1.\"3x+-+6y+=+9\"
\n" ); document.write( "2.\"x+-2y+=+3\"
\n" ); document.write( "The easiest way to solve is to use equation 2 and solve for x. Then substitute your value for x into equation 1.
\n" ); document.write( "2. \"x-2y=3\"
\n" ); document.write( "\"x-2y%2B2y=3%2B2y\" Additive inverse of 2y.
\n" ); document.write( "\"x=3%2B2y\"
\n" ); document.write( "Now use your result from equation 2 and plug it into the value for x in equation 1.
\n" ); document.write( "1. \"3x-6y=9\"
\n" ); document.write( "\"3%283%2B2y%29-6y=9\" Substitute.
\n" ); document.write( "\"9+%2B+6y+-+6y+=+9\"
\n" ); document.write( "\"9=9\"
\n" ); document.write( "Huh? What happened?
\n" ); document.write( "The problem you've run into is the equations are dependent, which means they are the same equation in disguise.
\n" ); document.write( "You don't have enough information to solve the equations.
\n" ); document.write( "In fact, if you multiply the second equation by 3, you get the first equation.
\n" ); document.write( "\"3%28x-2y%29=3%2A3\"
\n" ); document.write( "\"3x-6y=9\"
\n" ); document.write( "The equations are dependent, there is no solution.
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