document.write( "Question 1139925: In a survey, the planning value for the population proportions P* = 0.5. How large a sample should be taken to provide a 90% confidence interval with a margin of error of 0.07?
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Algebra.Com's Answer #760439 by Boreal(15235)\"\" \"About 
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margin of error is z*sqrt(p*(1-p)/n)=0.07 and z(0.95)=1.645 for a CI of 90%\r
\n" ); document.write( "\n" ); document.write( "square both sides and 1.645^2*0.25/n=0.0049
\n" ); document.write( "2.706025*0.25=0.0049n
\n" ); document.write( "n=138.06
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