document.write( "Question 104406: The age of Nando is 8 years more 3 times his brother's age.find the age of each if 10 years from now ando will be 5 years more than twice his brother's age. \n" ); document.write( "

Algebra.Com's Answer #76042 by Fombitz(32388) $\"\"$ $\"About$

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\n" ); document.write( "Let N be Nando's age and B be his brother's age.
\n" ); document.write( "1. $\"N=3%2AB%2B8\"$ Age relationship now.
\n" ); document.write( "2. $\"%28N%2B10%29=2%2A%28B%2B10%29%2B5\"$ Age relationship in ten years.
\n" ); document.write( "Use equation 1 to solve equation 2 by substitution
\n" ); document.write( " $\"%28N%2B10%29=2%2A%28B%2B10%29%2B5\"$
\n" ); document.write( " $\"%283B%2B8%29%2B10=2B%2B20%2B5\"$
\n" ); document.write( " $\"3B%2B18=2B%2B25\"$
\n" ); document.write( " $\"B=7\"$
\n" ); document.write( "Substitute back into equation 1.
\n" ); document.write( " $\"N=3B%2B8\"$
\n" ); document.write( " $\"N=3%287%29%2B8\"$
\n" ); document.write( " $\"N=29\"$
\n" ); document.write( "Let's verify
\n" ); document.write( "1. $\"N=3%2AB%2B8\"$ Age relationship now.
\n" ); document.write( "29=3*7+8
\n" ); document.write( "29=29
\n" ); document.write( "Good answer
\n" ); document.write( "2. $\"%28N%2B10%29=2%2A%28B%2B10%29%2B5\"$ Age relationship in ten years.
\n" ); document.write( "29+10=2*(7+10)+5
\n" ); document.write( "39=2*17+5
\n" ); document.write( "39=39
\n" ); document.write( "Good answer.
\n" ); document.write( " \n" ); document.write( "

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