document.write( "Question 1139659: Sydney buys a new car for $22,000 and finances the car for 5 years at 3% interest
\n" ); document.write( "compounded yearly. She estimates that the value of the car will decrease by 14% each
\n" ); document.write( "year. If Sydney is able to sell the car on the day of her last car payment for the value she
\n" ); document.write( "estimated, how much money will she have spent over the 5 years?
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Algebra.Com's Answer #760154 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Use compound interest formula with
\n" ); document.write( "yearly compounding:
\n" ); document.write( "\"+A+=+A%5B0%5D%2A%28+1+%2B+r+%29%5Et+\"
\n" ); document.write( "\"+A+=+22000%2A%28+1+%2B+.03+%29%5E5+\"
\n" ); document.write( "\"+A++=+22000%2A1.03%5E5+\"
\n" ); document.write( "\"+A+=+22000%2A1.159274+\"
\n" ); document.write( "\"+A+=+25504.03+\"
\n" ); document.write( "The interest plus principal over 5 years is:
\n" ); document.write( "$25,504.03
\n" ); document.write( "--------------------
\n" ); document.write( "The depreciated value of the car after 5 yrs:
\n" ); document.write( "\"+A+=+A%5B0%5D%2A%28+1+-+.14+%29%5E5+\"
\n" ); document.write( "\"+A+=+22000%2A.86%5E5+\"
\n" ); document.write( "\"+A+=+22000%2A.47043+\"
\n" ); document.write( "\"+A+=+10349.39+\"
\n" ); document.write( "$10,349.39
\n" ); document.write( "----------------------
\n" ); document.write( "Over the 5 years, she has spent:
\n" ); document.write( "\"+25504.03+-+10349.39+=+15154.64+\"
\n" ); document.write( "$15,154.64
\n" ); document.write( "
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