document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1139573>Question 1139573</A>: <I><SPAN STYLE=\"word-break: break-all;\"> please explain:\r<BR>\n" );
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document.write( "Determine whether there is a maximum or minimum value for f(x) = -2x^2 + 3x + 4 and find that value </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #760054 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=760054\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Determine whether there is a maximum or minimum value for f(x) = -2x^2 + 3x + 4 and find that value<BR>\n" );
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document.write( "The coefficient of the x^2 term is negative --> a maximum<BR>\n" );
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document.write( "The max is the vertex of the parabola at x = -b/(2a) = -3/-4 = 3/4<BR>\n" );
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document.write( "f(3/4) = -2*(3/4)^2 + 3*(3/4) + 4 = -9/8 + 9/4 + 4 = 41/8\r<BR>\n" );
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