document.write( "Question 1139502: Last year, at Haven's Pond Car Dealership, for a particular model of BMW, Jeep, and Toyota, one could purchase all three cars for a total of $140,000. This year, due to inflation, the same cars would cost $151,830. The cost of the BMW increased by 8%, the Jeep by 4%, and the Toyota by 10%. If the price of last year's Jeep was $6,000 less than the price of last year's BMW, what was the price of each of the three cars last year? (Round your answers to the nearest integer.) \n" ); document.write( "
Algebra.Com's Answer #759972 by greenestamps(13215)\"\" \"About 
You can put this solution on YOUR website!


\n" ); document.write( "The numbers are ugly enough I don't care to take the time to work the problem all the way through. I'll let you do that.

\n" ); document.write( "Here are two basic ways to set up the problem for solving:

\n" ); document.write( "(1) 3 variables, 3 equations

\n" ); document.write( "b+j+t = 140000 (this year's cost of the BMW, Jeep, and Toyota is $140,000
\n" ); document.write( "j = b-6000 (this year the cost of the jeep is $6000 less than the cost of the BMW)
\n" ); document.write( "1.08b+1.04j+1.10t = 151,830 (next year's cost of the three, with the given percent increases, is $151,830)

\n" ); document.write( "You would probably solve this system by a combination of substitution and elimination....

\n" ); document.write( "(2) 1 variable, 1 equation

\n" ); document.write( "Let x be the cost of the BMW
\n" ); document.write( "Then the cost of the Jeep is x-6000
\n" ); document.write( "Then the cost of the Toyota is 140000-(2x-6000) ($140,000 minus the cost of the other two)

\n" ); document.write( "Then the equation (still ugly; but easier to solve than the system of 3 equations) is

\n" ); document.write( "1.08(x)+1.04(x-6000)+1.10(140000-(2x-6000)) = 151830

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