document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=104375>Question 104375</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Angela needs 20 quarts of 50% antifreeze in her radiator. She plans to obtain this by mixing some pure antifreeze(100%) with a appopriate amount of a 40% antifreeze soluation. how many quarts of each should she use?\r<BR>\n" );
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document.write( " every time I do this I come up short when I back check. I would like to Thank you in advance for any help </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #75993 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=75993\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x=(amount of pure antifreeze), so 20-x=(amount of 40% antifreeze)\r<BR>\n" );
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document.write( "x(100%)+(20-x)(40%)=20(50%) </SPAN>\n" );
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