document.write( "Question 1138783: The one-to-one functions g and h are defined as follows. \r
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document.write( "g = {(-7,4), (4,-7), (8,5), (9,-4)}
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document.write( "h(x) = 3x-13\r
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document.write( "Find the following.\r
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document.write( "g^-1(-7) =\r
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document.write( "h^-1(x) =\r
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document.write( "(h*h^1)(8) = \n" );
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Algebra.Com's Answer #759883 by adamsmith9037(4)![]() ![]() ![]() You can put this solution on YOUR website! g^-1(-7) = 4 (note that inverse functions swap the x and y coordinates and the \n" ); document.write( "coordinate (4,-7) is swapped to (-7,4)\r \n" ); document.write( "\n" ); document.write( "h^(-1)x=.... \n" ); document.write( "let y = 3x-13 \n" ); document.write( "swapping the x and y, \n" ); document.write( "x = 3y-13 \n" ); document.write( "making y the subject of the equation, \n" ); document.write( "y = (x+13/3) \n" ); document.write( "and hence h^(-1)x=(x+13/3)\r \n" ); document.write( "\n" ); document.write( "h(x) = 3x-13 \n" ); document.write( "h(h(x)) = 3(3x-13) - 13 \n" ); document.write( "h(h(x)) = 9x - 39 - 13 \n" ); document.write( "h(h(x)) = 9x - 52 \n" ); document.write( "when x = 8, \n" ); document.write( "9(8) - 52 = 72 - 52 = 20 \n" ); document.write( " \n" ); document.write( " |