document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=104378>Question 104378</A>: <I><SPAN STYLE=\"word-break: break-all;\"> THE WIDTH OF A PHOTOGRAPH IS 4 CENTIMETERS MORE THAN THREE TENTHS OF THE LENGTH. IF THE WIDHT IS 13cm.FIND THE LENGHT\r<BR>\n" );
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document.write( "PLEASEEEEE HELPPPPPP  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #75954 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=75954\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> THE WIDTH OF A PHOTOGRAPH IS 4 CENTIMETERS MORE THAN THREE TENTHS OF THE LENGTH. IF THE WIDHT IS 13cm.FIND THE LENGHT <BR>\n" );
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document.write( "Let the length be \"x\" cm.<BR>\n" );
document.write( "Width is (3/10)x+4<BR>\n" );
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document.write( "EQUATION:<BR>\n" );
document.write( "(3/10)x+4 = 13<BR>\n" );
document.write( "Multiply thru by 10 to get:<BR>\n" );
document.write( "3x + 40 = 130<BR>\n" );
document.write( "3x = 90<BR>\n" );
document.write( "x = 30 cm (The length)<BR>\n" );
document.write( "===============<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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