document.write( "Question 104295: complete the ordered pairs so that each is a solution for the given equation: \r
\n" ); document.write( "\n" ); document.write( "3x+4y=12 (0 ), (,3/4), (, 0), (8/3,)
\n" ); document.write( "

Algebra.Com's Answer #75926 by elima(1433)\"\" \"About 
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3x+4y=12 (0 ), (,3/4), (, 0), (8/3,)
\n" ); document.write( "3(0)+4y=12
\n" ); document.write( "4y=12
\n" ); document.write( "y=3
\n" ); document.write( "======
\n" ); document.write( "3x+4y=12
\n" ); document.write( "3x+4(3/4)=12
\n" ); document.write( "3x+12/4=12
\n" ); document.write( "3x+3=10
\n" ); document.write( "3x=12
\n" ); document.write( "x=9
\n" ); document.write( "=============
\n" ); document.write( "3x+4y=12
\n" ); document.write( "3x+4(0)=12
\n" ); document.write( "3x=12
\n" ); document.write( "x=4
\n" ); document.write( "=============
\n" ); document.write( "3x+4y=12
\n" ); document.write( "3(8/3)+4y=12
\n" ); document.write( "24/3+4y=12
\n" ); document.write( "8+4y=12
\n" ); document.write( "4y=4
\n" ); document.write( "y=1
\n" ); document.write( "===========
\n" ); document.write( ":)
\n" ); document.write( "
\n" );