document.write( "Question 104329: A consultant traveled 8 hours to attend a meeting. The return trip took only 7 hours because the speed was 3 miles per hour faster. What was the consultant’s speed each way \n" ); document.write( "
Algebra.Com's Answer #75909 by stanbon(75887)\"\" \"About 
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A consultant traveled 8 hours to attend a meeting. The return trip took only 7 hours because the speed was 3 miles per hour faster. What was the consultant’s speed each way
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\n" ); document.write( "To the meeting DATA:
\n" ); document.write( "Time = 8 hrs ; rate = x mph ; distance = 8x miles
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\n" ); document.write( "From the meeting DATA:
\n" ); document.write( "Time = 7 hrs ; rate = x+3 mph ; distance = 7(x+3) miles
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\n" ); document.write( "EQUATION:
\n" ); document.write( "distance to = distance from
\n" ); document.write( "8x = 7x+21
\n" ); document.write( "x = 21 mph (rate to the meeting)
\n" ); document.write( "x+3 = 24 mph ( rate from the meeting)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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