document.write( "Question 104213: John invested $7000 into two funds. One fund paid 14% interest per year and the other paid 11% interest per year. The total interest for the year was $902. How much money was invested at each rate? \n" ); document.write( "
Algebra.Com's Answer #75861 by jayanthihemkos@yahoo.com(87)\"\" \"About 
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John invested $7000 into two funds. One fund paid 14% interest per year and the other paid 11% interest per year. The total interest for the year was $902. How much money was invested at each rate?\r
\n" ); document.write( "\n" ); document.write( " Let one fund = x\r
\n" ); document.write( "\n" ); document.write( " The other fund = 7000-x\r
\n" ); document.write( "\n" ); document.write( " Interest paid for first fund = 14% of x = (14/100)x
\n" ); document.write( " Interest paid for the second fund = 11% of (7000-x) = (11/100)(7000-x)
\n" ); document.write( " Total interest = $902
\n" ); document.write( " (14/100)x +(11/100)(7000-x) = $902\r
\n" ); document.write( "\n" ); document.write( " (14x + 77000-11x)/100 = $902
\n" ); document.write( "
\n" ); document.write( " (3x+77000)/100 = $902
\n" ); document.write( "
\n" ); document.write( " (3x+77000) /100*100 = 902*100\r
\n" ); document.write( "\n" ); document.write( " 3x +77000 = 90200
\n" ); document.write( " 3x +77000-77000 = 90200-77000
\n" ); document.write( "3x = 13200
\n" ); document.write( "3x/3 = 13200/3
\n" ); document.write( "x = $4400--- interest paid for the first fund
\n" ); document.write( "7000-x = 7000-4400 = $2600 Interest paid for the second fund\r
\n" ); document.write( "\n" ); document.write( " First fund interest = $4400
\n" ); document.write( " Second fund interest = $2600
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