document.write( "Question 15293: How many liters of antifreeze must be added to 5 liters of water to make no less than a 60% solution and no more than an 80% solution? \n" ); document.write( "

Algebra.Com's Answer #7585 by rapaljer(4671) $\"\"$ $\"About$

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x = amount of antifreeze at 100%
\n" ); document.write( "5 = amount of water at 0%
\n" ); document.write( "x+5 = total mixture at 60% or 80%\r
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\n" ); document.write( "\n" ); document.write( "x = .6(x+5)
\n" ); document.write( "x = .6x + 3.0
\n" ); document.write( "x - .6x = 3.0
\n" ); document.write( "1.0x - .6x = 3.0
\n" ); document.write( ".4x = 3.0
\n" ); document.write( "x = 3.0/.4 = 30/4 = 7.5 liters for the minimum of 60%\r
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\n" ); document.write( "\n" ); document.write( "x = .8(x+5)
\n" ); document.write( "x = .8x + 4.0
\n" ); document.write( "x - .8x = 4.0
\n" ); document.write( "1.0x - .8x = 4.0
\n" ); document.write( ".2x = 4.0
\n" ); document.write( "x = 4.0/.2 = 40/2 = 20 liters for the maximum of 80%\r
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\n" ); document.write( "\n" ); document.write( "In other words, you should use between 7.5 and 20 liters (inclusive!) of antifreeze.\r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC\r
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