document.write( "Question 104207: Richie put on his jogging shoes and speed-walked to the park at 5 miles per hour. Then he ran back at 9 miles per hour. If the total trip took 4 2/3 hours, how far was it to the park? \n" ); document.write( "
Algebra.Com's Answer #75810 by checkley75(3666)![]() ![]() ![]() You can put this solution on YOUR website! D/5+D/9=4 2/3 \n" ); document.write( "(9D+5D)/45=14/3 NOW CROSS MULTIPLY \n" ); document.write( "14D*3=14*45 \n" ); document.write( "42D=630 \n" ); document.write( "D=630/42 \n" ); document.write( "D=15 MILES IS THE DISTANCE TO THE PARK. \n" ); document.write( "PROOF: \n" ); document.write( "15/5+15/9=4 2/3 \n" ); document.write( "3+1 2/3=4 2/3 \n" ); document.write( "4 2/3=4 2/3 \n" ); document.write( " \n" ); document.write( " |