document.write( "Question 104155: Hello! I'm having problems with substitution and for the following problem i keep getting X=7 y=4 and z=1. I thought this made sense but my answer sheet says it should be x=2 y=1 and z=1. Could you show me how its done so i can compare it to the way i've been trying?\r
\n" ); document.write( "\n" ); document.write( "here's the equation and thank you!!!\r
\n" ); document.write( "\n" ); document.write( "-3x-3y+2z=-7
\n" ); document.write( "z=1
\n" ); document.write( "-2x-3y+z=-6
\n" ); document.write( "

Algebra.Com's Answer #75780 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
-3x-3y+2z=-7
\n" ); document.write( "z=1
\n" ); document.write( "-2x-3y+z=-6
\n" ); document.write( "----------------
\n" ); document.write( "Substitute z for z and rewrite the equations:
\n" ); document.write( "-3x-3y=-9
\n" ); document.write( "-2x-3y=-7
\n" ); document.write( "------------
\n" ); document.write( "Subtract the 1st equation by the 2nd to get:
\n" ); document.write( "x = 2
\n" ); document.write( "-------
\n" ); document.write( "Substitute into -2x-3y=-7 to solve for y:
\n" ); document.write( "-2*2-3y = -7
\n" ); document.write( "-3y = -3
\n" ); document.write( "y = 1
\n" ); document.write( "================
\n" ); document.write( "Solution:
\n" ); document.write( "x = 2; y = 1, z = 1
\n" ); document.write( "==============
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "
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