document.write( "Question 104155: Hello! I'm having problems with substitution and for the following problem i keep getting X=7 y=4 and z=1. I thought this made sense but my answer sheet says it should be x=2 y=1 and z=1. Could you show me how its done so i can compare it to the way i've been trying?\r
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document.write( "here's the equation and thank you!!!\r
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document.write( "-3x-3y+2z=-7
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document.write( "z=1
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document.write( "-2x-3y+z=-6 \n" );
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Algebra.Com's Answer #75780 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! -3x-3y+2z=-7 \n" ); document.write( "z=1 \n" ); document.write( "-2x-3y+z=-6 \n" ); document.write( "---------------- \n" ); document.write( "Substitute z for z and rewrite the equations: \n" ); document.write( "-3x-3y=-9 \n" ); document.write( "-2x-3y=-7 \n" ); document.write( "------------ \n" ); document.write( "Subtract the 1st equation by the 2nd to get: \n" ); document.write( "x = 2 \n" ); document.write( "------- \n" ); document.write( "Substitute into -2x-3y=-7 to solve for y: \n" ); document.write( "-2*2-3y = -7 \n" ); document.write( "-3y = -3 \n" ); document.write( "y = 1 \n" ); document.write( "================ \n" ); document.write( "Solution: \n" ); document.write( "x = 2; y = 1, z = 1 \n" ); document.write( "============== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |