document.write( "Question 104145: solve for g\r
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document.write( "40= (2)(1+g)/ 13.8-g\r
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document.write( "I am confused because we are solving for a varible that shows up in the equation more than once. \n" );
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Algebra.Com's Answer #75769 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! 40 = (2)(1+g)/ 13.8-g \n" ); document.write( ": \n" ); document.write( "I am assuming you mean: \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "2 + 2g - 13.8g = 13.8(40); multiplied eq by 13.8, gets rid of the denominator \n" ); document.write( ": \n" ); document.write( "2g - 13.8g = 552 - 2; Subtracted 2 from both sides \n" ); document.write( ": \n" ); document.write( "-11.8g = 550; do the math \n" ); document.write( ": \n" ); document.write( "g = 550/-11.8; divide both sides by -11.8 \n" ); document.write( ": \n" ); document.write( "g = -46.61 is the solution \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check in original equation: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "-6.61 + 46.61 = 40; confirms our solution \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "If this is NOT the way you meant the problem to be, let us know, we can edit this solution\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |