document.write( "Question 104042: two cars pas each other traveling in opposite directions on a highway, one is goig 1.5 times as fast as the other. at the end of 3.5 hours they are 192.5 miles apart. find each cars rate.
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Algebra.Com's Answer #75768 by ankor@dixie-net.com(22740)\"\" \"About 
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Two cars pass each other traveling in opposite directions on a highway, one is going 1.5 times as fast as the other. At the end of 3.5 hours, they are 192.5 miles apart. Find each cars rate.
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\n" ); document.write( "Let s = speed of the slower car
\n" ); document.write( "Then
\n" ); document.write( "(1.5s) = speed of the faster car
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\n" ); document.write( "Write a distance equation: Distance = time * speed.
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\n" ); document.write( "They both will be traveling for 3.5 hr
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\n" ); document.write( "Fast car dist + slow car dist = 192.5
\n" ); document.write( "3.5(1.5s) + 3.5s = 192.5
\n" ); document.write( "5.25s + 3.5s = 192.5
\n" ); document.write( "8.75s = 192.5
\n" ); document.write( "s = 192.5/8.75
\n" ); document.write( "s = 22 mph is the slow car
\n" ); document.write( "Then
\n" ); document.write( "1.5(22)) = 33 mph is the fast car
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\n" ); document.write( "Check solution:
\n" ); document.write( "3.5(33) + 3.5(22) =
\n" ); document.write( "115.5 + 77 = 192.5: confirms out solution \n" ); document.write( "
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