document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=104029>Question 104029</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One recipe calls for 1/4 teaspoon vanilla.  A second recipe requires for 1/8  teaspoon vanilla flour, and a third recipe calls for 1/2 teaspoon vanilla.  How much vanilla is required to make all three recipes? Help. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #75765 by </B><A HREF=/tutors/aboutme.mpl?userid=TP><B>TP(29)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=TP><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=75765\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You need to work out 1/4+1/8+1/2.<BR>\n" );
document.write( "The bottom numbers of the fractions (the DENOMINATORS) are 2,4 and 8 and they have an LCM (Lowest Common Multiple or the smallest number that is in EACH of the times tables of 2,4 and 8) of 8.<BR>\n" );
document.write( "Since the LCM is 8 change your fractions to eighths and then you can add them together.<BR>\n" );
document.write( "1/4 = 2/8 ( 1/4= 1/4*(2/2)= (1*2)/4*2)=2/8 ).\r<BR>\n" );
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document.write( "1/8=1/8 (no change needed )\r<BR>\n" );
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document.write( "and 1/2 =4/8 ( 1/2=1/2*(4/4)= (1*4)/(2*4)=4/8 ).\r<BR>\n" );
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document.write( "So 1/4+1/8+1/2 = (2/8)+(1/8)+(4/8) = 7/8.\r<BR>\n" );
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document.write( "And so 7/8ths of a teaspoon are needed.ANS </SPAN>\n" );
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