document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=104097>Question 104097</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rectangle is three times as long as it is wide. If its length and width are both decreased by 2 cm, its area is decreased by 36 cm (squared). find its original dimensions.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #75754 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=75754\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L=3w<BR>\n" );
document.write( "(3w-2)(w-2)+36=3w^2<BR>\n" );
document.write( "3w^2-8w+4+36=3w^2 subtract 3w^2 from each side.<BR>\n" );
document.write( "-8w+40=0 <BR>\n" );
document.write( "-8w=-40 subtract 40 from each side.<BR>\n" );
document.write( "w=5 divide each side by -8<BR>\n" );
document.write( "L=15<BR>\n" );
document.write( "Check:<BR>\n" );
document.write( "5*15=75<BR>\n" );
document.write( "3*13=39<BR>\n" );
document.write( "75-39=36<BR>\n" );
document.write( "Ed </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );