document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=104079>Question 104079</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Janet invested $29,000, part at 12% and part at 14%.  If the total interest at the end of the year is $3,800, how much did she invest at 12%?\r<BR>\n" );
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document.write( "I am having a terrible time setting up this problem...<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #75734 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=75734\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First assign a variable to the unknown.<BR>\n" );
document.write( "Let x = the amount that Janet invested at 12% per annum.  Then ($29,000-x), the remainder, is the amount Janet invested at at 14% per annum.<BR>\n" );
document.write( "We can express the interest earned on these two amounts as follows:<BR>\n" );
document.write( "First, we'll need to change the percentages to their decimal equivalents: (12% = 0.12 and 14% = 0.14)<BR>\n" );
document.write( "The amount of interest earned by (x) at 12% per annum can be expressed algebraically as:<BR>\n" );
document.write( "0.12x <BR>\n" );
document.write( "and the amount of interest earned by ($29,000-x) at 14% per annum can be expressed algebraically as: 0.14($29,000-x)<BR>\n" );
document.write( "Now the problem tells us that the sum of these two = $3,800<BR>\n" );
document.write( "So we can set up the necessary equation to solve for x.<BR>\n" );
document.write( "0.12x + 0.14($29,000-x) = $3,800 This is the equation you will need to compute x, the amount invested at 12% per annum. Let's solve this for x.<BR>\n" );
document.write( "0.12x + 0.14($29,000-x) = $3,800 Simplifying this, we get:<BR>\n" );
document.write( "0.12x + $4,060 - 0.14x = $3,800 Combining like-terms (the x-terms), gives us:<BR>\n" );
document.write( "-0.02x + $4,060 = $3,800 Now subtract $4,060 from both sides of the equation.<BR>\n" );
document.write( "-0.02x = -$260 Dividing both sides by -0.02, we have:<BR>\n" );
document.write( "x = $13,000 This is the amount Janet invested at 12% per annum.<BR>\n" );
document.write( "If you need to know the amount she invested at 14%, you would subtract $13,000 from $29,000 to get $16,000 invested at 14% per annum.\r<BR>\n" );
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