document.write( "Question 1139281: What is n in the equation?\r
\n" ); document.write( "\n" ); document.write( "n!/84 = (n-2)!/[(n-2)-(n-4)]\r
\n" ); document.write( "\n" ); document.write( "do I cancel n-2 and n-4 on the right side?
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Algebra.Com's Answer #757074 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "You can't cancel the (n-2) and (n-4) in the denominator on the right; they are not factors.

\n" ); document.write( "The denominator on the right is simply (n-2)-(n-4) = 2.

\n" ); document.write( "Then write the n! on the left as n(n-1)(n-2)!; do some canceling of common factors; cross-multiply; and solve.
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